Question 70726
THE THREE CONSECUTINE NUMBERS ARE X, (X+1), (X+2)
X/4+(X+1)/5=(X+2)/7-5 FIND A COMMON DENOMINATOR
(5X+4[X+1])/20=(X+2)/7-35/7
(5X+4X+4)/20=(X-33)/7
(9X+4)/20=(X-33)/7 NOW CROSS MULTIPLY
20(X-33)=7(9X+4)
20X-660=63X+28
20X-63X=28+660
-43X=688
X=688/-43
X=-16 ANSWER
X+1=-15 ANSWER
X=2=-14 ANSWER
PROOF
-16/4+-15/5=-14/7-5
-4-3=-2-5
-7=-7