Question 837817
{{{7y -3x = 25}}}....eq.1
{{{y = 3x + 1}}}....eq.2 ......substitute {{{y}}} in eq.1
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{{{7(3x+1) – 3x = 25}}} ....eq.1....solve for {{{x}}}

{{{21x+7 – 3x = 25}}}

{{{18x = 25-7}}}

{{{18x = 18}}}

{{{highlight(x = 1)}}}

go back to eq.2 and solve for {{{y}}}

{{{y = 3*1 + 1}}} ....eq.2

{{{y = 3 + 1}}}

{{{highlight(y = 4)}}}


{{{ graph( 600, 600, -5, 5, -10, 10, (3/7)x+25/7,3x+1) }}}