Question 837607
Kendra has $13.20 in dimes and quarters. If she has 4 times as many quarters as dimes, how many of each coin does she have?


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1st.) Label variables
d=dimes
q=quarters


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2nd.) Get information from second sentence: 4 times as many quarters as dimes.
So:

q=4d


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3rd.) Make equation.


0.10d+(4d*0.25)=$13.20


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4th.) Solve for "d".


0.10d+(4d*0.25)=$13.20
0.10d+1d=$13.20
1.10d=$13.20
1.10d/1.10=$13.20/1.10
d=12

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5th.) Solve for "q". Use the equation we made in step 2 and plug in the value we got for "d" in step 4.


q=4d
q=4(12)
q=48


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6th) Check work, using values we got for "q" and "d".


0.10d+(0.25q)=$13.20
0.10(12)+[0.25(48)]=$13.20
0.10(12)+[12]=$13.20
0.10(12)+[12]=$13.20
1.20+[12]=$13.20
$13.20=$13.20


Checks!

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Kendra has 48 quarters and 12 dimes.