Question 837613
Hello.  This is how it would look if m^(-1/3) was factored out of 3m^(2/3)-4m^(-1/3):


{{{m^(-1/3)(3m - 4)}}}


This is why:


When you multiply m^(-1/3) by 3m, you are ADDING the exponents.  So, you would add -1/3 and 1, which would be 1 - 1/3 = 2/3, hence 3m^(2/3)


When you multiply m^(-1/3) by 4, you get 4m^(-1/3), which gives you your original equation.  So, again, the answer is


{{{m^(-1/3)(3m-4)}}}