Question 70645
{{{((1/x)/(2/x)-(1/(1-x)))}}}
:
Let's deal with the {{{(1/x)/(2/x)}}} first, 
when you divide fractions, invert the dividing fraction and multiply
{{{(1/x)*(x/2)}}}; cancel the x's and you have {{{1/2}}}
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Now the problems is
{{{1/2 - 1/((x-1))}}}
:
The common denominator is 2(x-1)
{{{(1(x-1) - 2)/2(x-1)}}} = {{{(x - 1 - 2)/(2x-2)}}} = {{{(x - 3)/(2x - 2)}}}
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