Question 70656
Solve for x:
{{{Log[3]x -Log[9]x = 2}}} Change the base of the first log from 3 to 9
{{{Log[3]x = (Log[9]x)/Log[9]3}}}
But {{{Log[9]3 = 1/2}}} So now you have:
{{{Log[3]x = 2Log[9]x}}}
{{{2Log[9]x-Log[9]x = 2}}} Subtract the logarithms.
{{{Log[9]x = 2}}} Rewrite in exponential form..
{{{9^2 = x}}}
{{{x = 81}}}