<PRE><B>Question 836878</B>
find all possible solutions between the interval of 0 is less than or equal to x which is less than or equal to 2pie for the following equation: 4cos^3x=3cosx 
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4cos^3(x)-3cos(x) = 0
Factor:
cos(x)[4cos^2(x)-3] = 0
cos(x) = 0 or cos(x) = +-sqrt(3)/2
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x = pi/2 or (3/2)pi OR x = (1/3)pi or (2/3)pi or (4/3)pi or (5/3)pi 
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Cheers,
Stan H.
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