Question 836728
Perpendicular lines in a plane have slopes {{{m[1]m[2]=-1}}}.
The line you are looking for is {{{y=(1/5)x+b}}}, since your given line is in slope-intercept form, y=mx+b.


Solve your equation for b, and use the point it must contain, the given point, to solve for the value of b.
{{{b=y-mx}}}
{{{b=y-(1/5)x}}}
{{{b=2-(1/5)(-3)}}}