Question 836698
The way one solves this type of equation is through the grouping method: 

so... 

{{{x^3+9x^2-x-9}}} then we group the 1st and 2nd terms together and factor

{{{x^3+9x^2}}} --> {{{x^2(x+9)}}} 

then it is the same idea with the 3rd and 4th terms:

{{{x+9}}} 

Except this time we have nothing to factor out...

The next step is to cancel out like terms in this case it is {{{x+9}}} 

so we are left with {{{x^2}}} 

This {{{x^2}}} is one of your two terms. The other one is {{{x+9}}}. Yup that common term is the other factor! 

So our factors are {{{(x^2)(x+9)}}}} 

However, we are not done since {{{x^2}}} can be factored even more: 

So ultimately our final answer is: 

{{{(x)(x)(x+9)}}}