Question 836559
so first we solve for y like one does any linear equation so...

{{{2x-y = 6}}} --> {{{-y = 6-2x}}} --> {{{y = 2x-6}}} 

Then we plug random x values to get the corresponding y values. For example, if x = 0 then y would equal to -6. So we could graph the point (2,-6) on the line. 

Ultimately the line looks this: 

*[invoke describe_linear_equation 2, 1,-6 ]

As for the second equation same thing solve for y. 

{{{5y-2x=10}}} --> {{{5y=10-2x}}} --> {{{y = 10/5 -2x/5}}} --> {{{y = -2x/5 + 5}}}

One again choose some random x values and plug them in the equation for the y value. 

Ultimately, the line looks like this:
 
*[invoke describe_linear_equation 2/5, 1,5  ]