Question 836539
{{{a(x-3) + 8 = b(x-1)}}}
{{{ax-3a+8=bx-b}}}
{{{ax-bx=3a-b-8}}}
{{{x(a-b)=3a-b-8}}}
{{{x=(3a-b-8)/(a-b)}}}
The only restriction is that {{{a}}} cannot equal {{{b}}}.