Question 70628
{{{5(2x+1)+4<8x+6}}}
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Operate on this just as you would on an equation.  For the first step, you can multiply
out the left side to get:
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{{{10x + 5 + 4 < 8x + 6}}}
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Combine the +5 and the +4 on the left side.  The inequality becomes:
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{{{10x + 9 < 8x + 6}}}
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Eliminate the +9 on the left side by adding -9 to both sides:
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{{{10x < 8x +6 -9}}}
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And add the +6 and -9 on the right side:
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{{{10x < 8x - 3}}}
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Get rid of the 8x on the right side by adding -8x to both sides. The inequality simplifies to:
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{{{2x < -3}}}
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Dividing both sides by 2 results in:
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{{{x < (-3/2)}}}
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This tells you that x can be anywhere on the number line below the value {{{-3/2}}}.
But x cannot equal {{{(-3/2)}}}and it cannot be any value to the right of {{{(-3/2)}}} 
on the number line.
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It doesn't happen in this problem, but remember this rule: if you multiply or divide an
inequality by a negative number you must change the inequality sign to the opposite
direction.  
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Hope this helps you see how to work with inequalities.