Question 836389
{{{ln(2x-1)-ln(3x)>0}}}
{{{ln((2x-1)/(3x))>0}}}
{{{((2x-1))/3x>1}}}
{{{2x-1>3x}}}
{{{-x>1}}}
{{{x<-1}}}
However when {{{x<1}}}, both {{{ln(2x-1)}}} and {{{ln(3x)}}} are not defined.
There are no solutions.