Question 70623
Let s=smaller number L=larger number

The equation would look like:
<pre>
             L=s+6  (the larger number is 6 greater than the smaller)
          s+3L=34           </pre>
Plug in (s+6) into L of 2nd equation to solve for s (this is possible since L=s+6)
<pre>
         {{{s+3*highlight((s+6))=34}}}
            s+3s+18=34  Distribute the 3 among (s+6)
            4s+18=34    Add the s terms
            4s=16       subtract 18 from both sides
            s=4       </pre>      Divide both sides by 4
The smaller number is 4 so the larger is only 6 more than the smaller
<pre>
             L=4+6
             L=10          </pre>
So the larger number is 10.