Question 836281
Slope of your given line is {{{(2/3)}}}.  
The product of slopes of two perpendicular lines is -1.
If the two slopes are {{{m[1]}}} and {{{m[2]}}}, and if line1 and line2 are perpendicular, then {{{m[1]*m[2]=-1}}}


You want the slope, m, so that {{{m=-(3/2)}}}, the negative reciprocal of {{{(2/3)}}}.


Now you want to find the y intercept.


 You have no specified point to be contained!  This means that all lines, {{{y=-(3/2)x+b}}} are perpendicular to {{{y=(2/3)x+3}}}, for all real numbers b.


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