Question 836225
<pre>
The sum of the interior angles of an n-sided polygon is given by the
formula (n-2)·180°.

The sum of the exterior angles of ANY polygon is 360°.

We are told that the sum of the exterior angles is twice the sum of the interior angles:

360° = 2[(n-2)180°]

360 = 360(n-2)

Divide both sides by 360

1 = n-2

Add 2 to both sides

3 = n

Edwin</pre>