Question 836178
It's not a linear equation, it's a rational equation (the ratio of two polynomials)
{{{(2x)/(x^2-4)= (4)/(x^2-4) - (3)/(x+2)}}}
 Get a common denominator for all terms,
{{{x^2-4=(x+2)(x-2)}}}
{{{(2x)/((x+2)(x-2))= (4)/((x+2)(x-2)) - (3(x-2))/((x+2)(x-2))}}}
{{{(2x)/((x+2)(x-2))= (4- (3(x-2)))/((x+2)(x-2))}}}
{{{(2x)/((x+2)(x-2))= (4- 3x+6)/((x+2)(x-2))}}}
{{{(2x)/((x+2)(x-2))= (10- 3x)/((x+2)(x-2))}}}
The numerators have to equal each other.
{{{2x=10-3x}}}
{{{5x=10}}}
{{{x=2}}}
However this value make the denominators of the first and second term equal to zero so it cannot be a solution.
There are no solutions to this equation.