Question 835945
1.{{{x^2 + y^2/4 =1}}}
2.{{{ x^2 + y^2 =4}}}
From eq. 1,
{{{x^2=1-y^2/4}}}
Substitute into eq. 2,
{{{(1-y^2/4)+y^2=4}}}
{{{1+(3/4)y^2=4}}}
{{{(3/4)y^2=3}}}
{{{y^2=4}}}
{{{y=0 +- 2}}}
Then,
{{{x^2=1-y^2/4}}}
{{{x^2=1-1}}}
{{{x=0}}}
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{{{drawing(300,300,-3,3,-3,3,grid(1),circle(0,2,0.12),circle(0,-2,0.12),
graph(300,300,-3,3,-3,3,sqrt(4-x^2),-sqrt(4-x^2),2*sqrt(1-x^2),-2*sqrt(1-x^2)))}}}