Question 835910
{{{f(x)=1/(2x+1)}}}
{{{g(x)=x/(x+1)}}}
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{{{m(x)=g(x)*f(x)=(1/(2x+1))*(x/(x+1))}}}
{{{m(x)=g(x)*f(x)=(x)/((2x+1)(x+1))}}}
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{{{f(2/3)=1/(2(2/3)+1)=1/(4/3+1)=1/(4/3+3/3)=1/(7/3)=3/7}}}
{{{g(2/3)=(2/3)/(2/3+1)=(2/3)/(5/3)=2/5}}}
{{{f(2/3)-g(2/3)=3/7-2/5=15/35-14/35=1/35}}}