<PRE><B>Question 835706</B>
Find the largest of three consecutive odd integers if the sum of twice the first, five times the second and ten less than the third is 124
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!st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
2(2x-1)+5(2x+1)+(2x+3)-10 = 124
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4x-2 + 10x+5 + 2x-7 = 124
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16x - 4 = 124
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16x = 128
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x = 8
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1st: 2x-1 = 15
2nd: 17
3rd: 19
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Cheers,
Stan H.
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