Question 835643
cos(theta)*sin(2theta) = 0


cos(theta)*2*sin(theta)*cos(theta) = 0


2*cos(theta)*cos(theta)*sin(theta) = 0


2*cos^2(theta)*sin(theta) = 0


cos^2(theta) = 0 or sin(theta) = 0


cos(theta) = sqrt(0) or sin(theta) = 0


cos(theta) = 0 or sin(theta) = 0


theta = arccos(0) or theta = arcsin(0)


theta = pi/2 or 3pi/2 or theta = 0 or pi


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If we're in the interval [0, 2pi), then the final answers are: theta = 0, theta = pi, theta = pi/2, theta = 3pi/2