Question 835601
Sec^2 X csc X
Divided by
Sec^2 X + csc^2 X 
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(1/cos^2)(1/sin)]/[1/cos^2+1/sin^2]
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= [1/(cos^2*sin)]/[(cos^2+sin^2)/(cos^2*sin^2]
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= [1/(cos^2*sin)]/[1/(cos^2*sin^2)]
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Invert the denominator and multiply to get:
= [cos^2*sin^2]/[cos^2*sin]
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= sin(x)
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Cheers,
Stan H.
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