Question 835455
For 0<(theta) Note: the answer must be given as a fraction.
If sec(theta)=9/5 the
csc(theta)=
Sin(theta)=
cos(theta)=
tan(theta)=
cot(theta)=
***
sec(theta)=9/5=hypotenuse/adjacent side
opposite side=&#8730;(9^2-5^2)=&#8730;(81-25)=&#8730;56
csc(theta)=hypotenuse/opposite side=9/&#8730;56=9&#8730;56/56
Sin(theta)=1/csc theta=&#8730;56/9
cos(theta)=1/sec theta=5/9
tan(theta)=opposite side/adjacent side=&#8730;56/5
cot(theta)=1/tan theta