Question 835473
*[tex \Large 2+2i = 2 \sqrt{2} e^{i \frac{\pi}{4}}] and *[tex \Large \sqrt{3} - i= 2e^{-i \frac{\pi}{6}]


Their product is *[tex \Large 4\sqrt{2}e^{i(\frac{\pi}{4} - \frac{\pi}{6})} = 4\sqrt{2}e^{i\frac{\pi}{12}}]