Question 835074
A surgical technique is performed on seven patients. You are told there is a 70% chance of success. 
Binomial Problem with n = 7 and p(success) = 0.7
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Find the probability that the surgery is successful for 
(a) exactly five patients::: 7C5*0.7^5*0.3^2 = binompdf(7,0.7,5) = 0.3177
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(b) at least five patients::: 1- binomcdf(7,0.7,4) = 0.6471
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(c) less than five patients:::binomcdf(7,0.7,4)= 0.3529
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Cheers,
Stan H.
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