Question 835278
By Heron's formula, the area of the triangle is *[tex \Large \sqrt{12(5)(4)(3)} = 12 \sqrt{5}]. Letting *[tex \Large a] be the altitude to the side of length 9, we have *[tex \Large 12 \sqrt{5} = \frac{1}{2} \times a \times 9], or *[tex \Large a = \frac{8 \sqrt{5}}{3}].