Question 70538
Mr. flores is tiling the kitchen counter for his wife.  She wants a pattern with decorative tiles mixed in with plain tiles.  the plain tiles cost 60 cents a piece, and the decorative tiles cost $1.30 a piece.  They budgeted $300.00 for the tile, and the job will require 430 tiles in all.  What is the most number of decorative tiles that Mr. Flores can buy and still stay within budget?
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Let number of plain tiles "x". Let number of decorative tiles be "y"
EQUATIONS:
1st: x+y=430
2nd: 0.60x+1.30y=300
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Multiply thru 2nd by 100 to get rid of the decimals:
3rd: 60x+130y = 30000
Solve 1st for x: x=430-y
Substitute into 3rd to get:
60(430-y) + 130y = 30000
25800 - 60y + 130y = 30000
70y = 4200
y=60 (# of decorative tiles)
430-y=430-60 = 370 (number of plain tiles)
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Cheers,
Stan H.