Question 70480
Help is needed. Thanks! 
Graph the following and justify your answer.
y=2^x
y=log2 (x)
:
For y=2^x
Let x=-1
y=2^-1
y=1/2  Plot (-1,1/2)
Let x=0
y=2^0
y=1  Plot (0,1)
Let x=1
y=2^1
y=2  Plot (1,2)
Let x=2
y=2^2
y=4  Plot (2,4)
Connect your points and you have:
{{{graph(300,200,-10,10,-10,10,2^x)}}}
For y=log2(x)
Let y=-1
-1=log2(x)
2^-1=x
1/2=x  Plot (1/2,-1)
Let y=0
0=log2(x)
2^0=x
1=x  Plot (1,0)
Let y=1
1=log2(x)
2^1=x
2=x Plot (2,1)
Let y=2
2=log2(x)
2^2=x
4=x Plot (4,2)
Connect the points and you have:
{{{graph(300,200,-10,10,-10,10,ln(x)/ln(2))}}}
Happy Calculating!!!