Question 835396
Complex roots always come in complex conjugate pairs so if {{{i}}} is a root then so is {{{-i}}}.
{{{P=(x-2)(x+i)(x-i)}}}
{{{P=(x-2)(x^2+1)}}}
{{{P=x(x^2+1)-2(x^2+1)}}}
{{{highlight(P=x^3-2x^2+x-2)}}}