Question 835199
y=3(x-3)(x-3). It asks to graph, find the x-intercept, and the axis of symmetry. 
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Remember this formula for a parabola: y=A(x-h)^2+k, (h,k)=(x,y)coordinates of the vertex.
y=3(x-3)(x-3)
y=3(x-3)^2+0
vertex:(3,0)
since A>0, parabola opens upward.
axis of symmetry: x=3
find the x-intercept:
set y=0
0=3(x-3)(x-3)
x-3=0
x=3
x-intercept:3
see graph below:
{{{ graph( 300, 300, -10, 10, -10, 10, 3(x-3)^2+0) }}}