Question 835373
Q:
sketch the graph of the equation.
{{{x = 2y^2-4}}} 
Label the x- and y-intercepts. (If an answer does not exist, enter DNE.)
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A:
To get the x-intercept/s, let y = 0 then solve for x:
{{{x = 2(0)^2-4 = -4}}} 
The x-intercept is (-4,0)

To get the y-intercept/s, let x = 0 then solve for y:
{{{0 = 2y^2-4}}} 
{{{y^2 = 2}}}
{{{y = sqrt(2)}}} or {{{y = -sqrt(2)}}}

(smaller y-value)
y-intercept 
(x, y) = (0, {{{-sqrt(2)}}})

(larger y-value)
y-intercept 
(x, y) = (0, {{{sqrt(2)}}})

Here's the graph:

{{{ graph( 400, 400, -6, 5, -10, 10, sqrt((x+4)/2), -sqrt((x+4)/2)) }}}