Question 826318
larry has a collection of nickels, dimes, and quarters totaling more than $7.50.<pre>$0.05n + $0.10d + $0.25q > $7.50

Clear of decimals:

          5n + 10d + 25q > 750

Divide through by 5

             n + 2d + 5q > 150</pre>The number of nickels is 3 times the number of dimes<pre>n = 3d</pre>and the number of quarters is 4 times the number of dimes.<pre>q = 4d

Substituting:

             n + 2d + 5q > 150
         3d + 2d + 5(4d) > 150
           3d + 2d + 20d > 150
                     25d > 150
                       d > 6</pre>find the least possible number of dimes in the collection.<pre>So the least possible number of dimes greater than 6 is 7.

Edwin</pre>