Question 834984
Solve 3^t+1 = 7^t-1 for t
Assume it is {{{3^((t+1)) = 7^((t-1))}}}
(t+1)*log(3) = (t-1)*log(7)
(t+1) = (t-1)*{{{log(7)/log(3)}}}
(t+1) = 1.7712(t-1)
t + 1 = 1.7712t - 1.7712
1 + 1.7712 = 1.7712t - t
2.7712 = .7712t
t = {{{(2.7712)/.7712}}}
t = 3.593 approx