Question 835040
a man has a daughter and a son. Son is 3 years older than the daughter. In 1 years the father will be 6 times as old as daughter now and in 10 years he will be 14 years older than combined ages of kids what is the mans age
---------
Equations:
s = d + 3
f+1 = 6d
f+10 = (s+10) + (d+10) + 14
----
f+10 = (d+13) + d+10 + 14
f = 2d +13+14
f = 2d + 27
----
f+1 = 2d + 28
6d = 2d + 28
4d = 28
daughter = 7 yrs (now)
----
son = d+3 = 10 yrs (now)
father = 6d-1 = 41 yrs
===============================
Cheers,
Stan H.
-------------------