Question 834677
what are the 6 trig functions for sec theta = -5
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Note:: arccos(-1/5) = 101.54 degrees is in QII where x<0 and y>0.
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sec = r/x, so r = 5 and x = -1
Then y = sqrt[5^2-1^2] = sqrt(24)
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sin = y/r = sqrt(24)/5
cos = x/r = -1/5
tan = y/x = -sqrt(24)
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csc, sec, and cot are inverse of sin, cos, tan
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Cheers,
Stan H.
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