Question 834599
Perpendicular line slopes have the following relationship:
{{{m*m[perp]=-1}}}
{{{2*m[perp]=-1}}}
{{{m[perp]=-1/2}}}
{{{y=-(1/2)x+b}}}
use the point to solve for {{{b}}}
{{{-2=-(1/2)(1)+b}}}
{{{-2=-1/2+b}}}
{{{b=-3/2}}}
{{{y=-(1/2)x-3/2}}}
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{{{ drawing(300,300,-5,5,-5,5,
grid(1),
circle(1,-2,0.25),
graph( 300, 300, -5, 5, -5, 5, 2x-3, -(1/2)x-3/2)) }}}