Question 834417
Four consecutive odd integers: n, (n+2), (n+4), (n+6)
:
the sum of three smallest of four consecutive odd integers is 30 greater than the largest integer.
n + (n+2) + (n+4) = (n+6) + 30
do the math
3n + 6 = n + 36
3n - n = 36 - 6
2n = 30
n = 15 is the 1st odd digit
:
 What is the largest integer? 15 + 6 = 21