Question 834384
Find all values of &#952; in radians with -2&#960; < &#952; < 2&#960; such that sin(&#952;) = sqrt(2)/2.
{{{sin(theta)=sqrt(2)/2}}}
{{{(theta)}}}=-7&#960;/4,-5&#960;/4,&#960;/4,3&#960;/4 (in quadrants I and II in which sin>0)