Question 833071
Solve for x in the following equation.
log5(x) = 1/2log5(9) + 1/3log5(64) - log5(3)
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{{{log(5,(x))=(1/2)log(5,(9))+(1/3)log(5,(64))-log(5,(3))}}}
{{{log(5,(x))=log(5,(3))+log(5,(4))-log(5,(3))}}}
{{{log(5,(x))=log(5,(3))+log(5,(4))-log(5,(3))}}}
{{{log(5,(x))=log(5,(4))}}}
{{{log(5,(x))-log(5,(4))=0}}}
convert to exponential form:
5^0=x/4=1
x=4