Question 833706
The equation for the motion of a projectile fired straight up at an initial velocity of 64ft/s is h=64t-16t^2, where h s the height in feet and t is the time in seconds. Fine the time the projectile needs to reach its highest point. How high will it go ? 
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h(t) = 64t-16t^2 is a parabola.
Max h is the vertex
t @ vertex = -b/2a = -64/-32 = 2 seconds
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Max h is h(2)