Question 833659
{{{4/x+4/(x-15)=1}}}
The common denominator is x(x-15); multiply the left and right members by it and you can clear the fractions.


{{{4(x-15)+4x=x(x-15)}}}
{{{4x-60+4x=x^2-15x}}}
{{{-60+8x=x^2-15x}}}
{{{x^2-23x+60=0}}}
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60=2*3*2*5
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{{{x=(23+- sqrt(23^2-4*60))/2}}}
{{{x=(23+- sqrt(23^2-240))/2}}}
{{{x=(23+- sqrt(289))/2}}}
{{{x=(23+- 17)/2}}}