Question 833433
A rectangular field is ten times as long as it is wide. If the perimeter of the field is 1210 feet, what are the dimensions of the field?
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let x=width of rectangle
10x=length of rectangle
perimeter=twice the width=twice the length
2x+2(10x)=1210
2x+20x=1210
22x=1210
x=55
10x=550
dimensions of the field? width=55 ft, length=550 ft