Question 833387
Let x = the 10's digit
Let y = the units
:
what is The SUM of the digits of a TWO-DIGIT number is ONE FOURTH of the number.
x + y = {{{1/4}}}(10x+y)
The number is FOUR TIMES the SUM of the DIGITS?
10x + y = 4(x+y)
10x + y = 4x + 4y
10x - 4x = 4y - y
6x = 3y
2x = y
there are several solutions
 x y
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 1 2
 2 4
 3 6
 4 8