Question 833257
Solve the simultaneous equation.

 {{{2x + 3y = 13}}}
 {{{2xy + 5y^2 - 4x^2 = 41}}}
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 {{{2x + 3y = 13}}}  --> 2x = 13 - 3y
 {{{2xy + 5y^2 - 4x^2 = 41}}}
Sub for 2x in the 2nd eqn
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 {{{(13-3y)*y + 5y^2 - (13-3y)^2 = 41}}}
{{{-3y^2 + 13y + 5y^2 - 169+78y-9y^2 = 41}}}
{{{-7y^2  + 91y -210 = 0}}}
{{{y^2 - 13y + 30 = 0}}}
y = 3, 10
Sub for y in the 1st eqn to find x