Question 833149
2n and 2n+2 are some even, consecutive numbers.


{{{((2n)+(2n+2))((2n)-(2n+2))=44}}}
{{{(2n)^2-(2n+2)^2=44}}}
{{{4n^2-(4n^2+8n+4)=44}}}
{{{4n^2-4n^2-8n-4=44}}}
{{{-8n-4=44}}}
{{{-8n=48}}}
{{{highlight(n=-6)}}}



ANSWER:  The numbers would be -12 and -10.
Does this work?
{{{(-12+(-10))(-12-(-10))}}}
{{{(-12)^2-(-10)^2}}}
{{{144-100}}}
{{{44}}}, YES.