Question 833022
Because of the minus sign in the co-efficient of  {{{v^2}}},
The function is a parabola with a peak.
The formula for the peak is:
{{{ v[max] = -b/(2a) }}} where
{{{ a = -.011 }}}
{{{ b = 1.446 }}}
{{{ v[max] = -1.446/(2*(-.011)) }}}
{{{ v[max] = 1.446/.022 }}}
You can finish this. You have the speed that gives 
you {{{ E(v) }}}. Now plug {{{ v[max] }}} back into the
equation to get {{{ E(v)[max] }}}