Question 832914
A triangle has a perimeter of 57 inches. Side A is 3 inches shorter than twice side B, and side C is 4 inches longer than side B. How many inches long is side A? 
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Equations:
A + B + C = 57 inches
A = 2B-3
C = B+4
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Substitute for A and C and solve for "B":
2B-3 + B + B+4 = 57
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4B + 1 = 57
4B = 56
B = 14 inches
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A = 2B-3 = 2*14-3 = 25 inches
C = B+4 = 18 inches
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Cheers,
Stan H.
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