Question 70363
Multiply:
{{{(x-1/3)(x+1/3)}}}
There is a couple of ways the answer might look:
You can notice that these are conjugates and thus result in the difference of perfect squares:
{{{highlight(x^2-1/9)}}}
Or if you give the terms a common denominator:
{{{(x-1/3)(x+1/3)}}}
{{{(3x/3-1/3)(3x/3+1/3)}}}
{{{((3x-1)/3)((3x+1)/3)}}}
{{{highlight((9x^2-1)/9)}}}
Happy Calculating!!!!