Question 832601
The second part of your description is a circle, {{{(x+3)^2+(y+1)^2=25}}}.


Solve for y as a function of x.
{{{(y+1)^2=25-(x+3)^2}}}
{{{y+1=0+- sqrt(25-(x+3)^2)}}}
{{{highlight(y=-1+- sqrt(25-(x+3)^2))}}}, which obviously is two different formulas for y.


Next, use x=1 for both branches of y, so you WILL find two values for y.
Obtain {{{y=-1+3}}} and {{{y=-1-3}}};
{{{highlight(y=2)}}} or {{{highlight(y=-4)}}}