Question 831986
Probabilities are outcomes that you're interested in divided by total outcomes.
Probabilities are always at least zero and at most 1.
Albert rolled the cube {{{11+15+8+15+11+6}}} times or  {{{66}}} times.
a) P(2)={{{15/66=5/22}}}
b) P(1 or 5)=P(1)+P(5)={{{11/66+11/66=1/6+1/6=2/3}}}
c) P(not a 5) means P(everything but a 5)={{{1-P(5)=1-11/66=1-1/6=5/6}}}
You could also get it by summing all the probabilities of the other numbers,
P(not a 5)=P(1)+P(2)+P(3)+P(4)+P(6)={{{11/66+15/66+8/66+15/66+6/66=55/66=5/6}}}
d) P(6)=6/66={{{1/11}}}